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A070764
Number of polyiamonds with n cells, with holes.
9
0, 0, 0, 0, 0, 0, 0, 0, 1, 4, 25, 108, 450, 1713, 6267, 21988, 75185, 251590, 828408, 2692630, 8661287, 27624040, 87479663, 275392248, 862593661, 2690285608, 8359581585, 25893044920, 79978118632, 246433568617, 757696112134, 2325224420164, 7123627399429, 21791318924996, 66570286462599, 203119558522513, 619084154962394, 1885038245845679, 5734606563668062, 17431545733501175
OFFSET
1,10
COMMENTS
The number of holes in a polyiamond can be calculated by the formula: H = A + 1 - s/2 where A is the area, s = A + Sum_{ i = 0..3 } (2-i)*E(i), and E(i) is the number of vertices adjacent to i groups of unoccupied cells in the triangular lattice. - John Mason, Sep 04 2025
CROSSREFS
KEYWORD
hard,nonn
AUTHOR
Joseph Myers, May 05 2002
EXTENSIONS
More terms from Joseph Myers, Nov 11 2003
a(29)-a(30) from Joseph Myers, Nov 21 2010
a(31)-a(40) from John Mason, Sep 23 2025
STATUS
approved